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1、试题题目:(1)x+yx-y?1(x+y)2(2)a-ba2+ab÷ab-a2a2b2-a4(3)x2+7x-84x-x3?x2-..

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试题原文

(1)
x+y
x-y
?
1
(x+y)2

(2)
a-b
a2+ab
÷
ab-a2
a2b2-a4

(3)
x2+7x-8
4x-x3
?
x2-4
3x+24

(4)
x2+2xy+y2
xy-y2
÷
xy+y2
x2-2xy+y2

(5)x÷
1
x
?x
(6)
x3+x2
1-x2
÷x?
1
x

(7)9a2
3a
4b
?4ab2
(8)
a-4
a2+4a+4
?
a2+5a+6
a2-a-2
÷
a+3
a-2

(9)
x2+xy
x2-xy
÷(x-y)?
x2-xy
xy

(10)(-
a2
b
)2
?(
b
a
)3
?(
1
ab
)4

(11)[
(x-y)2
x+y
]3
?(
x2
y2-x2
)3

(12)(
x-1
x2-x-2
)2
÷
x2-2x+1
2-x
÷(
1
x2+x
)2

  试题来源:不详   试题题型:解答题   试题难度:中档   适用学段:初中   考察重点:分式的乘除



2、试题答案:该试题的参考答案和解析内容如下:
(1)原式=
1
(x-y)(x+y)
=
1
x2-y2


(2)原式=
a-b
a(a+b)
×
a2(b+a)(b-a)
-a(a-b)

=a-b;

(3)原式=
(x-1)(x+8)
x(2-x)(2+x)
?
(x+2)(x-2)
3(x+8)

=
1-x
3x


(4)原式=
(x+y)2
y(x-y)
×
(x-y)2
y(x+y)

=
x2-y2
y2


(5)原式=x?x?x
=x3

(6)原式=
x2(x+1)
(1+x)(1-x)
×
1
x
?
1
x

=
1
1-x


(7)原式=9a2b?
4b
3a
?4ab2
=48a2b3

(8)原式=
a-4
(a+2)2
?
(a+2)(a+3)
(a+1)(a-2)
?
a-2
a+3

=
a-4
(a+2)(a+1)


(9)原式=
x(x+y)
x(x-y)
?
1
x-y
?
x(x-y)
xy

=
x+y
y(x-y)


(10)原式=
a4
b2
?
b3
a3
?
1
a4b4

=
1
a3b3


(11)原式=[
(x-y)2
x+y
?
x2
-(x+y)(x-y)
]3
=[
x-y
-(x+y)2
]3
=-
(x-y)3
(x+y)6


(12)原式=[
x-1
(x+1)(x-2)
]2?
2-x
(x-1)2
?x2(x+1)2
=
(x-1)2
(x+1)2(x-2)2
?
2-x
(x-1)2
?x2(x+1)2
=
x2
2-x
3、扩展分析:该试题重点查考的考点详细输入如下:

    经过对同学们试题原文答题和答案批改分析后,可以看出该题目“(1)x+yx-y?1(x+y)2(2)a-ba2+ab÷ab-a2a2b2-a4(3)x2+7x-84x-x3?x2-..”的主要目的是检查您对于考点“初中分式的乘除”相关知识的理解。有关该知识点的概要说明可查看:“初中分式的乘除”。


4、其他试题:看看身边同学们查询过的数学试题:

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